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12563121340 = 22571137259101
BaseRepresentation
bin10111011001101001…
…00000010010111100
31012102112201200121101
423230310200102330
5201212124340330
65434343142444
7623216524630
oct135464402274
935375650541
1012563121340
115367611010
122527444a24
131252a1a513
14872724dc0
154d7e064ca
hex2ecd204bc

12563121340 has 288 divisors, whose sum is σ = 34718906880. Its totient is φ = 3708288000.

The previous prime is 12563121323. The next prime is 12563121367. The reversal of 12563121340 is 4312136521.

It is a Harshad number since it is a multiple of its sum of digits (28).

It is a junction number, because it is equal to n+sod(n) for n = 12563121299 and 12563121308.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 124387290 + ... + 124387390.

It is an arithmetic number, because the mean of its divisors is an integer number (120551760).

Almost surely, 212563121340 is an apocalyptic number.

12563121340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12563121340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17359453440).

12563121340 is an abundant number, since it is smaller than the sum of its proper divisors (22155785540).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12563121340 is a wasteful number, since it uses less digits than its factorization.

12563121340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 261 (or 222 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 12563121340 its reverse (4312136521), we get a palindrome (16875257861).

It can be divided in two parts, 12563 and 121340, that added together give a triangular number (133903 = T517).

The spelling of 12563121340 in words is "twelve billion, five hundred sixty-three million, one hundred twenty-one thousand, three hundred forty".