Base | Representation |
---|---|
bin | 111010100011100101… |
… | …0100010010100100111 |
3 | 110000120121001001121002 |
4 | 1311013022202110213 |
5 | 4030012441332233 |
6 | 133433503543515 |
7 | 12041103221033 |
oct | 1650712422447 |
9 | 400517031532 |
10 | 125747995943 |
11 | 49369513599 |
12 | 204548bab9b |
13 | bb1ccbb4bb |
14 | 612c8b71c3 |
15 | 340e9106e8 |
hex | 1d472a2527 |
125747995943 has 2 divisors, whose sum is σ = 125747995944. Its totient is φ = 125747995942.
The previous prime is 125747995937. The next prime is 125747995969. The reversal of 125747995943 is 349599747521.
It is a weak prime.
It is an emirp because it is prime and its reverse (349599747521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 125747995943 - 24 = 125747995927 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 125747995943.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125747995903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62873997971 + 62873997972.
It is an arithmetic number, because the mean of its divisors is an integer number (62873997972).
Almost surely, 2125747995943 is an apocalyptic number.
125747995943 is a deficient number, since it is larger than the sum of its proper divisors (1).
125747995943 is an equidigital number, since it uses as much as digits as its factorization.
125747995943 is an evil number, because the sum of its binary digits is even.
The product of its digits is 85730400, while the sum is 65.
The spelling of 125747995943 in words is "one hundred twenty-five billion, seven hundred forty-seven million, nine hundred ninety-five thousand, nine hundred forty-three".
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