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12576161398303 is a prime number
BaseRepresentation
bin1011011100000001110110…
…1000011111111000011111
31122112021021022101201102201
42313000131220133320133
53122021434304221203
642425224144232331
72435412001052026
oct267003550377037
948467238351381
1012576161398303
11400957a282088
1214b141700b6a7
13702c08610ac9
14316991c3b8bd
1516c20502de1d
hexb701da1fe1f

12576161398303 has 2 divisors, whose sum is σ = 12576161398304. Its totient is φ = 12576161398302.

The previous prime is 12576161398267. The next prime is 12576161398319. The reversal of 12576161398303 is 30389316167521.

It is a strong prime.

It is an emirp because it is prime and its reverse (30389316167521) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12576161398303 is a prime.

It is a super-2 number, since 2×125761613983032 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12576161398363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6288080699151 + 6288080699152.

It is an arithmetic number, because the mean of its divisors is an integer number (6288080699152).

Almost surely, 212576161398303 is an apocalyptic number.

12576161398303 is a deficient number, since it is larger than the sum of its proper divisors (1).

12576161398303 is an equidigital number, since it uses as much as digits as its factorization.

12576161398303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4898880, while the sum is 55.

The spelling of 12576161398303 in words is "twelve trillion, five hundred seventy-six billion, one hundred sixty-one million, three hundred ninety-eight thousand, three hundred three".