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125999483 is a prime number
BaseRepresentation
bin1111000001010…
…01100101111011
322210002102210112
413200221211323
5224223440413
620300334535
73056656301
oct740514573
9283072715
10125999483
116513a305
123624444b
132014790c
1412a3c271
15b0dd2a8
hex782997b

125999483 has 2 divisors, whose sum is σ = 125999484. Its totient is φ = 125999482.

The previous prime is 125999479. The next prime is 125999491. The reversal of 125999483 is 384999521.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (384999521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 125999483 - 22 = 125999479 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (125999183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62999741 + 62999742.

It is an arithmetic number, because the mean of its divisors is an integer number (62999742).

Almost surely, 2125999483 is an apocalyptic number.

125999483 is a deficient number, since it is larger than the sum of its proper divisors (1).

125999483 is an equidigital number, since it uses as much as digits as its factorization.

125999483 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 699840, while the sum is 50.

The square root of 125999483 is about 11224.9491312879. The cubic root of 125999483 is about 501.3291078143.

The spelling of 125999483 in words is "one hundred twenty-five million, nine hundred ninety-nine thousand, four hundred eighty-three".