Base | Representation |
---|---|
bin | 1011011101100110011000… |
… | …0000110010111101110100 |
3 | 1122121211220212210200222011 |
4 | 2313121212000302331310 |
5 | 3122442220224000002 |
6 | 42445445524014004 |
7 | 2440355460311413 |
oct | 267314600627564 |
9 | 48554825720864 |
10 | 12603145531252 |
11 | 4019a670a8601 |
12 | 14b66a7b31304 |
13 | 705618c27493 |
14 | 317dd190d47a |
15 | 16cc83ecc8d7 |
hex | b7666032f74 |
12603145531252 has 24 divisors (see below), whose sum is σ = 22066230295872. Its totient is φ = 6298508673600.
The previous prime is 12603145531211. The next prime is 12603145531253. The reversal of 12603145531252 is 25213554130621.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12603145531253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 175811377 + ... + 175883047.
It is an arithmetic number, because the mean of its divisors is an integer number (919426262328).
Almost surely, 212603145531252 is an apocalyptic number.
It is an amenable number.
12603145531252 is a deficient number, since it is larger than the sum of its proper divisors (9463084764620).
12603145531252 is a wasteful number, since it uses less digits than its factorization.
12603145531252 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 92439 (or 92437 counting only the distinct ones).
The product of its (nonzero) digits is 216000, while the sum is 40.
Adding to 12603145531252 its reverse (25213554130621), we get a palindrome (37816699661873).
The spelling of 12603145531252 in words is "twelve trillion, six hundred three billion, one hundred forty-five million, five hundred thirty-one thousand, two hundred fifty-two".
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