Base | Representation |
---|---|
bin | 1011011101101101001101… |
… | …0111111000100011100111 |
3 | 1122122000122202020121112111 |
4 | 2313123103113320203213 |
5 | 3123004444424100012 |
6 | 42450351545301451 |
7 | 2440452106505434 |
oct | 267332327704347 |
9 | 48560582217474 |
10 | 12604980300007 |
11 | 401a81884a517 |
12 | 14b6b1a494887 |
13 | 70584c09bc74 |
14 | 318127476b8b |
15 | 16cd40102ba7 |
hex | b76d35f88e7 |
12604980300007 has 2 divisors, whose sum is σ = 12604980300008. Its totient is φ = 12604980300006.
The previous prime is 12604980299983. The next prime is 12604980300019. The reversal of 12604980300007 is 70000308940621.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12604980300007 - 239 = 12055224486119 is a prime.
It is a super-4 number, since 4×126049803000074 (a number of 54 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12604980300047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6302490150003 + 6302490150004.
It is an arithmetic number, because the mean of its divisors is an integer number (6302490150004).
Almost surely, 212604980300007 is an apocalyptic number.
12604980300007 is a deficient number, since it is larger than the sum of its proper divisors (1).
12604980300007 is an equidigital number, since it uses as much as digits as its factorization.
12604980300007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72576, while the sum is 40.
The spelling of 12604980300007 in words is "twelve trillion, six hundred four billion, nine hundred eighty million, three hundred thousand, seven".
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