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12606054041813 is a prime number
BaseRepresentation
bin1011011101110001001101…
…0111111000100011010101
31122122010102120200100101112
42313130103113320203111
53123014144313314223
642451050303304405
72440520525246141
oct267342327704325
948563376610345
1012606054041813
11402021995a641
1214b7179bab105
13705990687b4b
143181c9cdc221
1516cda44ed778
hexb77135f88d5

12606054041813 has 2 divisors, whose sum is σ = 12606054041814. Its totient is φ = 12606054041812.

The previous prime is 12606054041773. The next prime is 12606054041831. The reversal of 12606054041813 is 31814045060621.

Together with next prime (12606054041831) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12424729666129 + 181324375684 = 3524873^2 + 425822^2 .

It is an emirp because it is prime and its reverse (31814045060621) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12606054041813 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12606054041873) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6303027020906 + 6303027020907.

It is an arithmetic number, because the mean of its divisors is an integer number (6303027020907).

Almost surely, 212606054041813 is an apocalyptic number.

It is an amenable number.

12606054041813 is a deficient number, since it is larger than the sum of its proper divisors (1).

12606054041813 is an equidigital number, since it uses as much as digits as its factorization.

12606054041813 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 41.

The spelling of 12606054041813 in words is "twelve trillion, six hundred six billion, fifty-four million, forty-one thousand, eight hundred thirteen".