126109433 has 2 divisors, whose sum is σ = 126109434. Its totient is φ = 126109432.

The previous prime is 126109427. The next prime is 126109439. The reversal of 126109433 is 334901621.

It is a balanced prime because it is at equal distance from previous prime (126109427) and next prime (126109439).

It can be written as a sum of positive squares in only one way, i.e., 123587689 + 2521744 = 11117^2 + 1588^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-126109433 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 126109396 and 126109405.

It is not a weakly prime, because it can be changed into another prime (126109439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63054716 + 63054717.

It is an arithmetic number, because the mean of its divisors is an integer number (63054717).

Almost surely, 2^126109433 is an apocalyptic number.

It is an amenable number.

126109433 is a deficient number, since it is larger than the sum of its proper divisors (1).

126109433 is an equidigital number, since it uses as much as digits as its factorization.

126109433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 29.

The square root of 126109433 is about 11229.8456356265. The cubic root of 126109433 is about 501.4748891264.

The spelling of 126109433 in words is "one hundred twenty-six million, one hundred nine thousand, four hundred thirty-three".