126120033131 has 2 divisors, whose sum is σ = 126120033132. Its totient is φ = 126120033130.

The previous prime is 126120033121. The next prime is 126120033133. The reversal of 126120033131 is 131330021621.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-126120033131 is a prime.

It is a super-2 number, since 2×126120033131² (a number of 23 digits) contains 22 as substring.

Together with 126120033133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 126120033097 and 126120033106.

It is not a weakly prime, because it can be changed into another prime (126120033133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63060016565 + 63060016566.

It is an arithmetic number, because the mean of its divisors is an integer number (63060016566).

Almost surely, 2^126120033131 is an apocalyptic number.

126120033131 is a deficient number, since it is larger than the sum of its proper divisors (1).

126120033131 is an equidigital number, since it uses as much as digits as its factorization.

126120033131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 126120033131 its reverse (131330021621), we get a palindrome (257450054752).

The spelling of 126120033131 in words is "one hundred twenty-six billion, one hundred twenty million, thirty-three thousand, one hundred thirty-one".