Base | Representation |
---|---|
bin | 1011011110001000100001… |
… | …1101011100101010000111 |
3 | 1122122201120210202210100021 |
4 | 2313202020131130222013 |
5 | 3123120004212330431 |
6 | 42454003343200011 |
7 | 2441131612032502 |
oct | 267421035345207 |
9 | 48581523683307 |
10 | 12612313401991 |
11 | 4022941127586 |
12 | 14b84262a6007 |
13 | 70644a3c2874 |
14 | 318621342139 |
15 | 16d11dcb8b11 |
hex | b788875ca87 |
12612313401991 has 2 divisors, whose sum is σ = 12612313401992. Its totient is φ = 12612313401990.
The previous prime is 12612313401949. The next prime is 12612313402037. The reversal of 12612313401991 is 19910431321621.
12612313401991 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12612313401991 - 233 = 12603723467399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12612313401091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6306156700995 + 6306156700996.
It is an arithmetic number, because the mean of its divisors is an integer number (6306156700996).
Almost surely, 212612313401991 is an apocalyptic number.
12612313401991 is a deficient number, since it is larger than the sum of its proper divisors (1).
12612313401991 is an equidigital number, since it uses as much as digits as its factorization.
12612313401991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69984, while the sum is 43.
The spelling of 12612313401991 in words is "twelve trillion, six hundred twelve billion, three hundred thirteen million, four hundred one thousand, nine hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •