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126132521441 is a prime number
BaseRepresentation
bin111010101111000010…
…1011000100111100001
3110001120101120222102012
41311132011120213201
54031304411141231
6133540001402305
712053452512443
oct1653605304741
9401511528365
10126132521441
114954657a263
1220541639395
13bb81872494
1461679b0493
153433568e2b
hex1d5e1589e1

126132521441 has 2 divisors, whose sum is σ = 126132521442. Its totient is φ = 126132521440.

The previous prime is 126132521399. The next prime is 126132521453. The reversal of 126132521441 is 144125231621.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91059097600 + 35073423841 = 301760^2 + 187279^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-126132521441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 126132521398 and 126132521407.

It is not a weakly prime, because it can be changed into another prime (126132521941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63066260720 + 63066260721.

It is an arithmetic number, because the mean of its divisors is an integer number (63066260721).

Almost surely, 2126132521441 is an apocalyptic number.

It is an amenable number.

126132521441 is a deficient number, since it is larger than the sum of its proper divisors (1).

126132521441 is an equidigital number, since it uses as much as digits as its factorization.

126132521441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 11520, while the sum is 32.

The spelling of 126132521441 in words is "one hundred twenty-six billion, one hundred thirty-two million, five hundred twenty-one thousand, four hundred forty-one".