126132525439 has 2 divisors, whose sum is σ = 126132525440. Its totient is φ = 126132525438.

The previous prime is 126132525397. The next prime is 126132525451. The reversal of 126132525439 is 934525231621.

It is a strong prime.

It is an emirp because it is prime and its reverse (934525231621) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-126132525439 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 126132525395 and 126132525404.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (126132525479) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63066262719 + 63066262720.

It is an arithmetic number, because the mean of its divisors is an integer number (63066262720).

Almost surely, 2^126132525439 is an apocalyptic number.

126132525439 is a deficient number, since it is larger than the sum of its proper divisors (1).

126132525439 is an equidigital number, since it uses as much as digits as its factorization.

126132525439 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 388800, while the sum is 43.

The spelling of 126132525439 in words is "one hundred twenty-six billion, one hundred thirty-two million, five hundred twenty-five thousand, four hundred thirty-nine".