Base | Representation |
---|---|
bin | 100101100101111… |
… | …1100011101100001 |
3 | 10020220120220021101 |
4 | 1023023330131201 |
5 | 10040411004213 |
6 | 325100354401 |
7 | 43154625265 |
oct | 11313743541 |
9 | 3226526241 |
10 | 1261422433 |
11 | 598049387 |
12 | 2b2545a01 |
13 | 17144ba0b |
14 | bd75c0a5 |
15 | 75b1ebdd |
hex | 4b2fc761 |
1261422433 has 2 divisors, whose sum is σ = 1261422434. Its totient is φ = 1261422432.
The previous prime is 1261422403. The next prime is 1261422443. The reversal of 1261422433 is 3342241621.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1207076049 + 54346384 = 34743^2 + 7372^2 .
It is a cyclic number.
It is not a de Polignac number, because 1261422433 - 25 = 1261422401 is a prime.
It is not a weakly prime, because it can be changed into another prime (1261422403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 630711216 + 630711217.
It is an arithmetic number, because the mean of its divisors is an integer number (630711217).
Almost surely, 21261422433 is an apocalyptic number.
It is an amenable number.
1261422433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1261422433 is an equidigital number, since it uses as much as digits as its factorization.
1261422433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6912, while the sum is 28.
The square root of 1261422433 is about 35516.5093020133. The cubic root of 1261422433 is about 1080.4885858034.
The spelling of 1261422433 in words is "one billion, two hundred sixty-one million, four hundred twenty-two thousand, four hundred thirty-three".
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