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12614443600013 is a prime number
BaseRepresentation
bin1011011110010000011101…
…1011100000100010001101
31122122221002021010001200022
42313210013123200202031
53123133340030200023
642454555000511525
72441235446311403
oct267440733404215
948587067101608
1012614443600013
114023834610912
1214b891b77b5a5
137066c9824878
1431878420d473
1516d1e5ce87c8
hexb79076e088d

12614443600013 has 2 divisors, whose sum is σ = 12614443600014. Its totient is φ = 12614443600012.

The previous prime is 12614443599943. The next prime is 12614443600021. The reversal of 12614443600013 is 31000634441621.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12468716645449 + 145726954564 = 3531107^2 + 381742^2 .

It is a cyclic number.

It is not a de Polignac number, because 12614443600013 - 218 = 12614443337869 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12614443600063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6307221800006 + 6307221800007.

It is an arithmetic number, because the mean of its divisors is an integer number (6307221800007).

Almost surely, 212614443600013 is an apocalyptic number.

It is an amenable number.

12614443600013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12614443600013 is an equidigital number, since it uses as much as digits as its factorization.

12614443600013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 35.

The spelling of 12614443600013 in words is "twelve trillion, six hundred fourteen billion, four hundred forty-three million, six hundred thousand, thirteen".