Base | Representation |
---|---|
bin | 10010010110110110001… |
… | …101001010010000000011 |
3 | 11110121002212112121201201 |
4 | 102112312031022100003 |
5 | 131132003433232044 |
6 | 2403303400042031 |
7 | 160065464544013 |
oct | 22266615122003 |
9 | 4417085477651 |
10 | 1261482320899 |
11 | 446a9a979849 |
12 | 184597a63317 |
13 | 91c5a187248 |
14 | 450adbdbc43 |
15 | 22c326447d4 |
hex | 125b634a403 |
1261482320899 has 2 divisors, whose sum is σ = 1261482320900. Its totient is φ = 1261482320898.
The previous prime is 1261482320873. The next prime is 1261482320911. The reversal of 1261482320899 is 9980232841621.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1261482320899 - 27 = 1261482320771 is a prime.
It is a super-2 number, since 2×12614823208992 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1261482320299) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 630741160449 + 630741160450.
It is an arithmetic number, because the mean of its divisors is an integer number (630741160450).
Almost surely, 21261482320899 is an apocalyptic number.
1261482320899 is a deficient number, since it is larger than the sum of its proper divisors (1).
1261482320899 is an equidigital number, since it uses as much as digits as its factorization.
1261482320899 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2985984, while the sum is 55.
The spelling of 1261482320899 in words is "one trillion, two hundred sixty-one billion, four hundred eighty-two million, three hundred twenty thousand, eight hundred ninety-nine".
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