Base | Representation |
---|---|
bin | 10111011111111101… |
… | …01110001101001011 |
3 | 1012120020110212202001 |
4 | 23233332232031023 |
5 | 201314212201103 |
6 | 5443515251431 |
7 | 624432230131 |
oct | 135776561513 |
9 | 35506425661 |
10 | 12616131403 |
11 | 5394528287 |
12 | 2541149b77 |
13 | 12609baa15 |
14 | 8797a3751 |
15 | 4dc8c801d |
hex | 2effae34b |
12616131403 has 2 divisors, whose sum is σ = 12616131404. Its totient is φ = 12616131402.
The previous prime is 12616131401. The next prime is 12616131421. The reversal of 12616131403 is 30413161621.
It is a weak prime.
It is an emirp because it is prime and its reverse (30413161621) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12616131403 - 21 = 12616131401 is a prime.
Together with 12616131401, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (12616131401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6308065701 + 6308065702.
It is an arithmetic number, because the mean of its divisors is an integer number (6308065702).
Almost surely, 212616131403 is an apocalyptic number.
12616131403 is a deficient number, since it is larger than the sum of its proper divisors (1).
12616131403 is an equidigital number, since it uses as much as digits as its factorization.
12616131403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 28.
The spelling of 12616131403 in words is "twelve billion, six hundred sixteen million, one hundred thirty-one thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •