Base | Representation |
---|---|
bin | 1011011110100110011010… |
… | …0101101100101101111101 |
3 | 1122200111021211221221212222 |
4 | 2313221212211230231331 |
5 | 3123232421234333143 |
6 | 42501411335335125 |
7 | 2441534445105041 |
oct | 267514645545575 |
9 | 48614254857788 |
10 | 12620335074173 |
11 | 4026288157622 |
12 | 14b9aa48214a5 |
13 | 707128283258 |
14 | 318b8284c021 |
15 | 16d43d145768 |
hex | b7a6696cb7d |
12620335074173 has 2 divisors, whose sum is σ = 12620335074174. Its totient is φ = 12620335074172.
The previous prime is 12620335074163. The next prime is 12620335074241. The reversal of 12620335074173 is 37147053302621.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11336675532004 + 1283659542169 = 3366998^2 + 1132987^2 .
It is a cyclic number.
It is not a de Polignac number, because 12620335074173 - 28 = 12620335073917 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12620335074163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6310167537086 + 6310167537087.
It is an arithmetic number, because the mean of its divisors is an integer number (6310167537087).
Almost surely, 212620335074173 is an apocalyptic number.
It is an amenable number.
12620335074173 is a deficient number, since it is larger than the sum of its proper divisors (1).
12620335074173 is an equidigital number, since it uses as much as digits as its factorization.
12620335074173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 635040, while the sum is 44.
Adding to 12620335074173 its reverse (37147053302621), we get a palindrome (49767388376794).
The spelling of 12620335074173 in words is "twelve trillion, six hundred twenty billion, three hundred thirty-five million, seventy-four thousand, one hundred seventy-three".
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