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12631324597 is a prime number
BaseRepresentation
bin10111100001110001…
…01011011110110101
31012121022001202212221
423300320223132311
5201332104341342
65445221042341
7625005326143
oct136070533665
935538052787
1012631324597
1153a2065141
1225462563b1
131263baa288
1487b7da593
154dddc9a67
hex2f0e2b7b5

12631324597 has 2 divisors, whose sum is σ = 12631324598. Its totient is φ = 12631324596.

The previous prime is 12631324493. The next prime is 12631324619. The reversal of 12631324597 is 79542313621.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11665296036 + 966028561 = 108006^2 + 31081^2 .

It is a cyclic number.

It is not a de Polignac number, because 12631324597 - 211 = 12631322549 is a prime.

It is a super-2 number, since 2×126313245972 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12631924597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6315662298 + 6315662299.

It is an arithmetic number, because the mean of its divisors is an integer number (6315662299).

Almost surely, 212631324597 is an apocalyptic number.

It is an amenable number.

12631324597 is a deficient number, since it is larger than the sum of its proper divisors (1).

12631324597 is an equidigital number, since it uses as much as digits as its factorization.

12631324597 is an evil number, because the sum of its binary digits is even.

The product of its digits is 272160, while the sum is 43.

The spelling of 12631324597 in words is "twelve billion, six hundred thirty-one million, three hundred twenty-four thousand, five hundred ninety-seven".