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126332313085471 is a prime number
BaseRepresentation
bin11100101110011000001000…
…101001010010011000011111
3121120022020210010000102201011
4130232120020221102120133
5113024312034122213341
61124404132522400051
735416131326261203
oct3456301051223037
9546266703012634
10126332313085471
1137287262295279
1212204070060027
135565116c5768c
14232a7336c2b03
15e912d79ceb81
hex72e608a5261f

126332313085471 has 2 divisors, whose sum is σ = 126332313085472. Its totient is φ = 126332313085470.

The previous prime is 126332313085399. The next prime is 126332313085519. The reversal of 126332313085471 is 174580313233621.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 126332313085471 - 213 = 126332313077279 is a prime.

It is a super-3 number, since 3×1263323130854713 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (126332313085171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63166156542735 + 63166156542736.

It is an arithmetic number, because the mean of its divisors is an integer number (63166156542736).

Almost surely, 2126332313085471 is an apocalyptic number.

126332313085471 is a deficient number, since it is larger than the sum of its proper divisors (1).

126332313085471 is an equidigital number, since it uses as much as digits as its factorization.

126332313085471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2177280, while the sum is 49.

The spelling of 126332313085471 in words is "one hundred twenty-six trillion, three hundred thirty-two billion, three hundred thirteen million, eighty-five thousand, four hundred seventy-one".