Base | Representation |
---|---|
bin | 11100101110011000001000… |
… | …101001010010011000011111 |
3 | 121120022020210010000102201011 |
4 | 130232120020221102120133 |
5 | 113024312034122213341 |
6 | 1124404132522400051 |
7 | 35416131326261203 |
oct | 3456301051223037 |
9 | 546266703012634 |
10 | 126332313085471 |
11 | 37287262295279 |
12 | 12204070060027 |
13 | 5565116c5768c |
14 | 232a7336c2b03 |
15 | e912d79ceb81 |
hex | 72e608a5261f |
126332313085471 has 2 divisors, whose sum is σ = 126332313085472. Its totient is φ = 126332313085470.
The previous prime is 126332313085399. The next prime is 126332313085519. The reversal of 126332313085471 is 174580313233621.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 126332313085471 - 213 = 126332313077279 is a prime.
It is a super-3 number, since 3×1263323130854713 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (126332313085171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63166156542735 + 63166156542736.
It is an arithmetic number, because the mean of its divisors is an integer number (63166156542736).
Almost surely, 2126332313085471 is an apocalyptic number.
126332313085471 is a deficient number, since it is larger than the sum of its proper divisors (1).
126332313085471 is an equidigital number, since it uses as much as digits as its factorization.
126332313085471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2177280, while the sum is 49.
The spelling of 126332313085471 in words is "one hundred twenty-six trillion, three hundred thirty-two billion, three hundred thirteen million, eighty-five thousand, four hundred seventy-one".
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