1263777501253 has 2 divisors, whose sum is σ = 1263777501254. Its totient is φ = 1263777501252.

The previous prime is 1263777501223. The next prime is 1263777501281. The reversal of 1263777501253 is 3521057773621.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 836313908004 + 427463593249 = 914502^2 + 653807^2 .

It is a cyclic number.

It is not a de Polignac number, because 1263777501253 - 2¹⁷ = 1263777370181 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1263777501197 and 1263777501206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1263777501223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 631888750626 + 631888750627.

It is an arithmetic number, because the mean of its divisors is an integer number (631888750627).

Almost surely, 2^{1263777501253} is an apocalyptic number.

It is an amenable number.

1263777501253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1263777501253 is an equidigital number, since it uses as much as digits as its factorization.

1263777501253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1852200, while the sum is 49.

The spelling of 1263777501253 in words is "one trillion, two hundred sixty-three billion, seven hundred seventy-seven million, five hundred one thousand, two hundred fifty-three".