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1264000251389 is a prime number
BaseRepresentation
bin10010011001001100010…
…010010011010111111101
311110211121100110202000112
4102121030102103113331
5131202133031021024
62404401304035405
7160215050602151
oct22311422232775
94424540422015
101264000251389
1144807220a237
12184b7b162b65
139226ba23b45
144526c399061
1522d2d71300e
hex1264c4935fd

1264000251389 has 2 divisors, whose sum is σ = 1264000251390. Its totient is φ = 1264000251388.

The previous prime is 1264000251301. The next prime is 1264000251413. The reversal of 1264000251389 is 9831520004621.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 730910434489 + 533089816900 = 854933^2 + 730130^2 .

It is a cyclic number.

It is not a de Polignac number, because 1264000251389 - 220 = 1263999202813 is a prime.

It is a super-2 number, since 2×12640002513892 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1264000251289) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 632000125694 + 632000125695.

It is an arithmetic number, because the mean of its divisors is an integer number (632000125695).

Almost surely, 21264000251389 is an apocalyptic number.

It is an amenable number.

1264000251389 is a deficient number, since it is larger than the sum of its proper divisors (1).

1264000251389 is an equidigital number, since it uses as much as digits as its factorization.

1264000251389 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 41.

The spelling of 1264000251389 in words is "one trillion, two hundred sixty-four billion, two hundred fifty-one thousand, three hundred eighty-nine".