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126404525153 is a prime number
BaseRepresentation
bin111010110111001001…
…0111111110001100001
3110002021100102012100202
41311232102333301201
54032334024301103
6134022555354545
712063264510254
oct1655622776141
9402240365322
10126404525153
1149676071715
12205b8752a55
13bbc601a31a
146191b7709b
15344c397988
hex1d6e4bfc61

126404525153 has 2 divisors, whose sum is σ = 126404525154. Its totient is φ = 126404525152.

The previous prime is 126404525123. The next prime is 126404525171. The reversal of 126404525153 is 351525404621.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73827410944 + 52577114209 = 271712^2 + 229297^2 .

It is an emirp because it is prime and its reverse (351525404621) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 126404525153 - 26 = 126404525089 is a prime.

It is not a weakly prime, because it can be changed into another prime (126404525123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63202262576 + 63202262577.

It is an arithmetic number, because the mean of its divisors is an integer number (63202262577).

Almost surely, 2126404525153 is an apocalyptic number.

It is an amenable number.

126404525153 is a deficient number, since it is larger than the sum of its proper divisors (1).

126404525153 is an equidigital number, since it uses as much as digits as its factorization.

126404525153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144000, while the sum is 38.

Adding to 126404525153 its reverse (351525404621), we get a palindrome (477929929774).

The spelling of 126404525153 in words is "one hundred twenty-six billion, four hundred four million, five hundred twenty-five thousand, one hundred fifty-three".