Base | Representation |
---|---|
bin | 10111100011001010… |
… | …11010001001100011 |
3 | 1012122010010111020012 |
4 | 23301211122021203 |
5 | 201343110100313 |
6 | 5450320235135 |
7 | 625210103216 |
oct | 136145321143 |
9 | 35563114205 |
10 | 12643050083 |
11 | 53a8743724 |
12 | 254a16baab |
13 | 1266454331 |
14 | 87d1ad77d |
15 | 4dee43da8 |
hex | 2f195a263 |
12643050083 has 2 divisors, whose sum is σ = 12643050084. Its totient is φ = 12643050082.
The previous prime is 12643050071. The next prime is 12643050107. The reversal of 12643050083 is 38005034621.
12643050083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12643050083 - 26 = 12643050019 is a prime.
It is not a weakly prime, because it can be changed into another prime (12643050583) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6321525041 + 6321525042.
It is an arithmetic number, because the mean of its divisors is an integer number (6321525042).
Almost surely, 212643050083 is an apocalyptic number.
12643050083 is a deficient number, since it is larger than the sum of its proper divisors (1).
12643050083 is an equidigital number, since it uses as much as digits as its factorization.
12643050083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 32.
The spelling of 12643050083 in words is "twelve billion, six hundred forty-three million, fifty thousand, eighty-three".
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