Base | Representation |
---|---|
bin | 10111100011001110… |
… | …00001000101010001 |
3 | 1012122010220220120112 |
4 | 23301213001011101 |
5 | 201343212043242 |
6 | 5450333251105 |
7 | 625213510343 |
oct | 136147010521 |
9 | 35563826515 |
10 | 12643471697 |
11 | 53a8a0146a |
12 | 254a333a95 |
13 | 12665711cc |
14 | 87d27d293 |
15 | 4deec8c82 |
hex | 2f19c1151 |
12643471697 has 2 divisors, whose sum is σ = 12643471698. Its totient is φ = 12643471696.
The previous prime is 12643471669. The next prime is 12643471699. The reversal of 12643471697 is 79617434621.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11774637121 + 868834576 = 108511^2 + 29476^2 .
It is a cyclic number.
It is not a de Polignac number, because 12643471697 - 216 = 12643406161 is a prime.
Together with 12643471699, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12643471699) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6321735848 + 6321735849.
It is an arithmetic number, because the mean of its divisors is an integer number (6321735849).
Almost surely, 212643471697 is an apocalyptic number.
It is an amenable number.
12643471697 is a deficient number, since it is larger than the sum of its proper divisors (1).
12643471697 is an equidigital number, since it uses as much as digits as its factorization.
12643471697 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1524096, while the sum is 50.
The spelling of 12643471697 in words is "twelve billion, six hundred forty-three million, four hundred seventy-one thousand, six hundred ninety-seven".
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