Base | Representation |
---|---|
bin | 11100101111111100100010… |
… | …011101011011001001110111 |
3 | 121120200120001101102201000101 |
4 | 130233330202131123021313 |
5 | 113033043331303200222 |
6 | 1124525442302454531 |
7 | 35426666024113462 |
oct | 3457744235331167 |
9 | 546616041381011 |
10 | 126440120365687 |
11 | 37318a54728577 |
12 | 12220b38594447 |
13 | 55723380a184b |
14 | 2331a3d5a22d9 |
15 | e93ee7347927 |
hex | 72ff2275b277 |
126440120365687 has 2 divisors, whose sum is σ = 126440120365688. Its totient is φ = 126440120365686.
The previous prime is 126440120365609. The next prime is 126440120365723. The reversal of 126440120365687 is 786563021044621.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-126440120365687 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (126440120365187) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63220060182843 + 63220060182844.
It is an arithmetic number, because the mean of its divisors is an integer number (63220060182844).
Almost surely, 2126440120365687 is an apocalyptic number.
126440120365687 is a deficient number, since it is larger than the sum of its proper divisors (1).
126440120365687 is an equidigital number, since it uses as much as digits as its factorization.
126440120365687 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11612160, while the sum is 55.
The spelling of 126440120365687 in words is "one hundred twenty-six trillion, four hundred forty billion, one hundred twenty million, three hundred sixty-five thousand, six hundred eighty-seven".
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