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12650125125133 is a prime number
BaseRepresentation
bin1011100000010101011000…
…1101101110011000001101
31122210100011222012100022201
42320011112031232120031
53124224424013001013
642523215351441501
72443640615261416
oct270052615563015
948710158170281
1012650125125133
114037984932851
121503819386291
13709b94cb9742
1431a3ab04480d
1516e0d35ec3dd
hexb815636e60d

12650125125133 has 2 divisors, whose sum is σ = 12650125125134. Its totient is φ = 12650125125132.

The previous prime is 12650125125107. The next prime is 12650125125167. The reversal of 12650125125133 is 33152152105621.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10484009361604 + 2166115763529 = 3237902^2 + 1471773^2 .

It is an emirp because it is prime and its reverse (33152152105621) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12650125125133 - 25 = 12650125125101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12650125125092 and 12650125125101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12650125125173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6325062562566 + 6325062562567.

It is an arithmetic number, because the mean of its divisors is an integer number (6325062562567).

Almost surely, 212650125125133 is an apocalyptic number.

It is an amenable number.

12650125125133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12650125125133 is an equidigital number, since it uses as much as digits as its factorization.

12650125125133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54000, while the sum is 37.

The spelling of 12650125125133 in words is "twelve trillion, six hundred fifty billion, one hundred twenty-five million, one hundred twenty-five thousand, one hundred thirty-three".