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12656331439 is a prime number
BaseRepresentation
bin10111100100110000…
…00100101010101111
31012200001010020211021
423302120010222233
5201410010101224
65451513035011
7625431020323
oct136230045257
935601106737
1012656331439
115405195154
1225526b5a67
13126912461b
14880c69983
154e11b91e4
hex2f2604aaf

12656331439 has 2 divisors, whose sum is σ = 12656331440. Its totient is φ = 12656331438.

The previous prime is 12656331403. The next prime is 12656331449. The reversal of 12656331439 is 93413365621.

12656331439 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (93413365621) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12656331439 - 213 = 12656323247 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12656331395 and 12656331404.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12656331449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6328165719 + 6328165720.

It is an arithmetic number, because the mean of its divisors is an integer number (6328165720).

Almost surely, 212656331439 is an apocalyptic number.

12656331439 is a deficient number, since it is larger than the sum of its proper divisors (1).

12656331439 is an equidigital number, since it uses as much as digits as its factorization.

12656331439 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 349920, while the sum is 43.

The spelling of 12656331439 in words is "twelve billion, six hundred fifty-six million, three hundred thirty-one thousand, four hundred thirty-nine".