Base | Representation |
---|---|
bin | 1011100001011111101101… |
… | …0101101001110011100111 |
3 | 1122212020200022222220200211 |
4 | 2320113323111221303213 |
5 | 3130041303240012013 |
6 | 42540315141320251 |
7 | 2445245164133515 |
oct | 270277325516347 |
9 | 48766608886624 |
10 | 12670075313383 |
11 | 404539222a534 |
12 | 1507666706087 |
13 | 70ba24273867 |
14 | 31b3408814b5 |
15 | 16e89ecc923d |
hex | b85fb569ce7 |
12670075313383 has 2 divisors, whose sum is σ = 12670075313384. Its totient is φ = 12670075313382.
The previous prime is 12670075313333. The next prime is 12670075313411. The reversal of 12670075313383 is 38331357007621.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12670075313383 - 213 = 12670075305191 is a prime.
It is a super-3 number, since 3×126700753133833 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12670075313303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6335037656691 + 6335037656692.
It is an arithmetic number, because the mean of its divisors is an integer number (6335037656692).
Almost surely, 212670075313383 is an apocalyptic number.
12670075313383 is a deficient number, since it is larger than the sum of its proper divisors (1).
12670075313383 is an equidigital number, since it uses as much as digits as its factorization.
12670075313383 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1905120, while the sum is 49.
The spelling of 12670075313383 in words is "twelve trillion, six hundred seventy billion, seventy-five million, three hundred thirteen thousand, three hundred eighty-three".
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