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1268933979149 is a prime number
BaseRepresentation
bin10010011101110010010…
…110111110110000001101
311111022100012011002011022
4102131302112332300031
5131242234044313044
62410535031003525
7160451236600124
oct22356226766015
94438305132138
101268933979149
1144a1741719a1
12185b175095a5
1392876c1a895
14455b9728abb
152301b9283ee
hex127725bec0d

1268933979149 has 2 divisors, whose sum is σ = 1268933979150. Its totient is φ = 1268933979148.

The previous prime is 1268933979121. The next prime is 1268933979191. The reversal of 1268933979149 is 9419793398621.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1166378400100 + 102555579049 = 1079990^2 + 320243^2 .

It is an emirp because it is prime and its reverse (9419793398621) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1268933979149 is a prime.

It is a super-2 number, since 2×12689339791492 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1268933979749) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 634466989574 + 634466989575.

It is an arithmetic number, because the mean of its divisors is an integer number (634466989575).

Almost surely, 21268933979149 is an apocalyptic number.

It is an amenable number.

1268933979149 is a deficient number, since it is larger than the sum of its proper divisors (1).

1268933979149 is an equidigital number, since it uses as much as digits as its factorization.

1268933979149 is an evil number, because the sum of its binary digits is even.

The product of its digits is 158723712, while the sum is 71.

The spelling of 1268933979149 in words is "one trillion, two hundred sixty-eight billion, nine hundred thirty-three million, nine hundred seventy-nine thousand, one hundred forty-nine".