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12694551351133 is a prime number
BaseRepresentation
bin1011100010111010111000…
…1110010100111101011101
31122221120212002222110102111
42320232232032110331131
53130441420121214013
642555444003554021
72450102550050251
oct270565616247535
948846762873374
1012694551351133
114054802322a03
12151035768b911
13711125085232
1431c5c33d6261
1517033399d73d
hexb8bae394f5d

12694551351133 has 2 divisors, whose sum is σ = 12694551351134. Its totient is φ = 12694551351132.

The previous prime is 12694551351059. The next prime is 12694551351137. The reversal of 12694551351133 is 33115315549621.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7024185501124 + 5670365850009 = 2650318^2 + 2381253^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12694551351133 is a prime.

It is a super-2 number, since 2×126945513511332 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12694551351137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6347275675566 + 6347275675567.

It is an arithmetic number, because the mean of its divisors is an integer number (6347275675567).

Almost surely, 212694551351133 is an apocalyptic number.

It is an amenable number.

12694551351133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12694551351133 is an equidigital number, since it uses as much as digits as its factorization.

12694551351133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1458000, while the sum is 49.

The spelling of 12694551351133 in words is "twelve trillion, six hundred ninety-four billion, five hundred fifty-one million, three hundred fifty-one thousand, one hundred thirty-three".