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126973435523953 is a prime number
BaseRepresentation
bin11100110111101101001110…
…100001010011001101110001
3121122120112122000222210211111
4130313231032201103031301
5113120313043443231303
61130014442505313321
735513346046136344
oct3467551641231561
9548515560883744
10126973435523953
113750414a187517
12122a8376795841
1355b070b373405
14234d79323445b
15ea2d0cb4db6d
hex737b4e853371

126973435523953 has 2 divisors, whose sum is σ = 126973435523954. Its totient is φ = 126973435523952.

The previous prime is 126973435523941. The next prime is 126973435523959. The reversal of 126973435523953 is 359325534379621.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105658519415089 + 21314916108864 = 10279033^2 + 4616808^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-126973435523953 is a prime.

It is a super-2 number, since 2×1269734355239532 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (126973435523959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63486717761976 + 63486717761977.

It is an arithmetic number, because the mean of its divisors is an integer number (63486717761977).

Almost surely, 2126973435523953 is an apocalyptic number.

It is an amenable number.

126973435523953 is a deficient number, since it is larger than the sum of its proper divisors (1).

126973435523953 is an equidigital number, since it uses as much as digits as its factorization.

126973435523953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 551124000, while the sum is 67.

The spelling of 126973435523953 in words is "one hundred twenty-six trillion, nine hundred seventy-three billion, four hundred thirty-five million, five hundred twenty-three thousand, nine hundred fifty-three".