Base | Representation |
---|---|
bin | 11100110111110010100110… |
… | …110100110011010101010011 |
3 | 121122121002112121110010021222 |
4 | 130313302212310303111103 |
5 | 113120411411232423142 |
6 | 1130021240015235255 |
7 | 35513642150306216 |
oct | 3467624664632523 |
9 | 548532477403258 |
10 | 126979211998547 |
11 | 37506643917367 |
12 | 122a9509218b2b |
13 | 55b111c038c0c |
14 | 234db8049977d |
15 | ea3049d31bd2 |
hex | 737ca6d33553 |
126979211998547 has 2 divisors, whose sum is σ = 126979211998548. Its totient is φ = 126979211998546.
The previous prime is 126979211998363. The next prime is 126979211998549. The reversal of 126979211998547 is 745899112979621.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 126979211998547 - 212 = 126979211994451 is a prime.
It is a super-2 number, since 2×1269792119985472 (a number of 29 digits) contains 22 as substring.
Together with 126979211998549, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (126979211998549) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63489605999273 + 63489605999274.
It is an arithmetic number, because the mean of its divisors is an integer number (63489605999274).
Almost surely, 2126979211998547 is an apocalyptic number.
126979211998547 is a deficient number, since it is larger than the sum of its proper divisors (1).
126979211998547 is an equidigital number, since it uses as much as digits as its factorization.
126979211998547 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1234517760, while the sum is 80.
The spelling of 126979211998547 in words is "one hundred twenty-six trillion, nine hundred seventy-nine billion, two hundred eleven million, nine hundred ninety-eight thousand, five hundred forty-seven".
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