Base | Representation |
---|---|
bin | 10111101001111001… |
… | …11100011100110001 |
3 | 1012210001110001122122 |
4 | 23310330330130301 |
5 | 202002041122122 |
6 | 5500055244025 |
7 | 626464256411 |
oct | 136474743461 |
9 | 35701401578 |
10 | 12699551537 |
11 | 5427625042 |
12 | 2565079615 |
13 | 1275077a4a |
14 | 8868ba641 |
15 | 4e4da5142 |
hex | 2f4f3c731 |
12699551537 has 2 divisors, whose sum is σ = 12699551538. Its totient is φ = 12699551536.
The previous prime is 12699551503. The next prime is 12699551549. The reversal of 12699551537 is 73515599621.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7264323361 + 5435228176 = 85231^2 + 73724^2 .
It is an emirp because it is prime and its reverse (73515599621) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12699551537 - 28 = 12699551281 is a prime.
It is a super-2 number, since 2×126995515372 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12699551597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6349775768 + 6349775769.
It is an arithmetic number, because the mean of its divisors is an integer number (6349775769).
Almost surely, 212699551537 is an apocalyptic number.
It is an amenable number.
12699551537 is a deficient number, since it is larger than the sum of its proper divisors (1).
12699551537 is an equidigital number, since it uses as much as digits as its factorization.
12699551537 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2551500, while the sum is 53.
The spelling of 12699551537 in words is "twelve billion, six hundred ninety-nine million, five hundred fifty-one thousand, five hundred thirty-seven".
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