Search a number
-
+
12707435113 is a prime number
BaseRepresentation
bin10111101010110110…
…00001001001101001
31012210121021120212221
423311123001021221
5202011100410423
65500540234041
7626621262532
oct136533011151
935717246787
1012707435113
11543101a09a
12256783b921
1312768a8199
1488796d689
154e5910e5d
hex2f56c1269

12707435113 has 2 divisors, whose sum is σ = 12707435114. Its totient is φ = 12707435112.

The previous prime is 12707435101. The next prime is 12707435123. The reversal of 12707435113 is 31153470721.

12707435113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9422196624 + 3285238489 = 97068^2 + 57317^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12707435113 is a prime.

It is a super-2 number, since 2×127074351132 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12707435123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6353717556 + 6353717557.

It is an arithmetic number, because the mean of its divisors is an integer number (6353717557).

Almost surely, 212707435113 is an apocalyptic number.

It is an amenable number.

12707435113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12707435113 is an equidigital number, since it uses as much as digits as its factorization.

12707435113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17640, while the sum is 34.

The spelling of 12707435113 in words is "twelve billion, seven hundred seven million, four hundred thirty-five thousand, one hundred thirteen".