Base | Representation |
---|---|
bin | 1011100011110100101111… |
… | …0001001111010111001111 |
3 | 1200000001221021210111110021 |
4 | 2320331023301033113033 |
5 | 3131220220313144142 |
6 | 43010532504323011 |
7 | 2451162421402441 |
oct | 270751361172717 |
9 | 50001837714407 |
10 | 12710079428047 |
11 | 4060350538a21 |
12 | 151336ba73467 |
13 | 71272b136c21 |
14 | 31d257800491 |
15 | 170941d25267 |
hex | b8f4bc4f5cf |
12710079428047 has 2 divisors, whose sum is σ = 12710079428048. Its totient is φ = 12710079428046.
The previous prime is 12710079428021. The next prime is 12710079428051. The reversal of 12710079428047 is 74082497001721.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12710079428047 is a prime.
It is a super-2 number, since 2×127100794280472 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12710079427985 and 12710079428003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12710079428087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6355039714023 + 6355039714024.
It is an arithmetic number, because the mean of its divisors is an integer number (6355039714024).
Almost surely, 212710079428047 is an apocalyptic number.
12710079428047 is a deficient number, since it is larger than the sum of its proper divisors (1).
12710079428047 is an equidigital number, since it uses as much as digits as its factorization.
12710079428047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1580544, while the sum is 52.
The spelling of 12710079428047 in words is "twelve trillion, seven hundred ten billion, seventy-nine million, four hundred twenty-eight thousand, forty-seven".
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