Base | Representation |
---|---|
bin | 1011100011111111000010… |
… | …1111101001101001001111 |
3 | 1200000100002011221112012021 |
4 | 2320333300233221221033 |
5 | 3131241402344031142 |
6 | 43012111300351011 |
7 | 2451321130460245 |
oct | 270776057515117 |
9 | 50010064845167 |
10 | 12712847252047 |
11 | 406154093a078 |
12 | 1513a029a5467 |
13 | 712a7c6a98c7 |
14 | 31d43b24a795 |
15 | 170a54d06267 |
hex | b8ff0be9a4f |
12712847252047 has 2 divisors, whose sum is σ = 12712847252048. Its totient is φ = 12712847252046.
The previous prime is 12712847252003. The next prime is 12712847252069. The reversal of 12712847252047 is 74025274821721.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12712847252047 - 215 = 12712847219279 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12712847251985 and 12712847252003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12712848252047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6356423626023 + 6356423626024.
It is an arithmetic number, because the mean of its divisors is an integer number (6356423626024).
Almost surely, 212712847252047 is an apocalyptic number.
12712847252047 is a deficient number, since it is larger than the sum of its proper divisors (1).
12712847252047 is an equidigital number, since it uses as much as digits as its factorization.
12712847252047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3512320, while the sum is 52.
The spelling of 12712847252047 in words is "twelve trillion, seven hundred twelve billion, eight hundred forty-seven million, two hundred fifty-two thousand, forty-seven".
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