Base | Representation |
---|---|
bin | 11100111010000001001101… |
… | …111111101110001111001011 |
3 | 121200010201210101202120101201 |
4 | 130322001031333232033023 |
5 | 113130414013132333231 |
6 | 1130215442502525031 |
7 | 35531002625222104 |
oct | 3472011577561713 |
9 | 550121711676351 |
10 | 127132340511691 |
11 | 37565582981769 |
12 | 12313123736777 |
13 | 55c26b37b7688 |
14 | 23573495473ab |
15 | ea700d3dd161 |
hex | 73a04dfee3cb |
127132340511691 has 2 divisors, whose sum is σ = 127132340511692. Its totient is φ = 127132340511690.
The previous prime is 127132340511689. The next prime is 127132340511713. The reversal of 127132340511691 is 196115043231721.
It is a weak prime.
It is an emirp because it is prime and its reverse (196115043231721) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 127132340511691 - 21 = 127132340511689 is a prime.
Together with 127132340511689, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (127132340511091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63566170255845 + 63566170255846.
It is an arithmetic number, because the mean of its divisors is an integer number (63566170255846).
Almost surely, 2127132340511691 is an apocalyptic number.
127132340511691 is a deficient number, since it is larger than the sum of its proper divisors (1).
127132340511691 is an equidigital number, since it uses as much as digits as its factorization.
127132340511691 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 272160, while the sum is 46.
The spelling of 127132340511691 in words is "one hundred twenty-seven trillion, one hundred thirty-two billion, three hundred forty million, five hundred eleven thousand, six hundred ninety-one".
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