Base | Representation |
---|---|
bin | 10010100000000111010… |
… | …111110111011111011011 |
3 | 11111112210102102010222211 |
4 | 102200013113313133123 |
5 | 131312344102013411 |
6 | 2412031055255551 |
7 | 160600214553334 |
oct | 22400727673733 |
9 | 4445712363884 |
10 | 1271434016731 |
11 | 4502373a115a |
12 | 1864b481a5b7 |
13 | 92b84b61168 |
14 | 4577578928b |
15 | 23116160221 |
hex | 128075f77db |
1271434016731 has 2 divisors, whose sum is σ = 1271434016732. Its totient is φ = 1271434016730.
The previous prime is 1271434016663. The next prime is 1271434016813. The reversal of 1271434016731 is 1376104341721.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1271434016731 is a prime.
It is a super-2 number, since 2×12714340167312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1271434014731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 635717008365 + 635717008366.
It is an arithmetic number, because the mean of its divisors is an integer number (635717008366).
Almost surely, 21271434016731 is an apocalyptic number.
1271434016731 is a deficient number, since it is larger than the sum of its proper divisors (1).
1271434016731 is an equidigital number, since it uses as much as digits as its factorization.
1271434016731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84672, while the sum is 40.
The spelling of 1271434016731 in words is "one trillion, two hundred seventy-one billion, four hundred thirty-four million, sixteen thousand, seven hundred thirty-one".
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