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127205230811797 is a prime number
BaseRepresentation
bin11100111011000101000110…
…100110001001101010010101
3121200101200221020201110122101
4130323011012212021222111
5113133112303041434142
61130313135403002101
735536163126442505
oct3473050646115225
9550350836643571
10127205230811797
1137593487618006
1212325286509331
1355c952b987978
14235aaa1d6ba05
15ea8d776240b7
hex73b146989a95

127205230811797 has 2 divisors, whose sum is σ = 127205230811798. Its totient is φ = 127205230811796.

The previous prime is 127205230811731. The next prime is 127205230811821. The reversal of 127205230811797 is 797118032502721.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97553568440241 + 29651662371556 = 9876921^2 + 5445334^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-127205230811797 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (127205230811717) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63602615405898 + 63602615405899.

It is an arithmetic number, because the mean of its divisors is an integer number (63602615405899).

Almost surely, 2127205230811797 is an apocalyptic number.

It is an amenable number.

127205230811797 is a deficient number, since it is larger than the sum of its proper divisors (1).

127205230811797 is an equidigital number, since it uses as much as digits as its factorization.

127205230811797 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2963520, while the sum is 55.

The spelling of 127205230811797 in words is "one hundred twenty-seven trillion, two hundred five billion, two hundred thirty million, eight hundred eleven thousand, seven hundred ninety-seven".