Base | Representation |
---|---|
bin | 11100111011111100111000… |
… | …000100011111111011010001 |
3 | 121200121102111210111022111222 |
4 | 130323330320010133323101 |
5 | 113140102424330314332 |
6 | 1130400442032214425 |
7 | 35543413141616516 |
oct | 3473747004377321 |
9 | 550542453438458 |
10 | 127265116651217 |
11 | 37606918611586 |
12 | 123349ba09a415 |
13 | 5602083883acc |
14 | 235d9435c530d |
15 | eaa6ced26712 |
hex | 73bf3811fed1 |
127265116651217 has 2 divisors, whose sum is σ = 127265116651218. Its totient is φ = 127265116651216.
The previous prime is 127265116651207. The next prime is 127265116651243. The reversal of 127265116651217 is 712156611562721.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 77129214840976 + 50135901810241 = 8782324^2 + 7080671^2 .
It is a cyclic number.
It is not a de Polignac number, because 127265116651217 - 216 = 127265116585681 is a prime.
It is not a weakly prime, because it can be changed into another prime (127265116651207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63632558325608 + 63632558325609.
It is an arithmetic number, because the mean of its divisors is an integer number (63632558325609).
Almost surely, 2127265116651217 is an apocalyptic number.
It is an amenable number.
127265116651217 is a deficient number, since it is larger than the sum of its proper divisors (1).
127265116651217 is an equidigital number, since it uses as much as digits as its factorization.
127265116651217 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2116800, while the sum is 53.
The spelling of 127265116651217 in words is "one hundred twenty-seven trillion, two hundred sixty-five billion, one hundred sixteen million, six hundred fifty-one thousand, two hundred seventeen".
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