Base | Representation |
---|---|
bin | 11100111100101010100011… |
… | …010110010011010010101111 |
3 | 121200210010002210022111022201 |
4 | 130330222203112103102233 |
5 | 113141403400221323211 |
6 | 1130435152421322331 |
7 | 35550100412002315 |
oct | 3474524326232257 |
9 | 550703083274281 |
10 | 127314161120431 |
11 | 376256a597416a |
12 | 12342406b663a7 |
13 | 560689b6864ac |
14 | 23620770620b5 |
15 | eabb008710c1 |
hex | 73caa35934af |
127314161120431 has 2 divisors, whose sum is σ = 127314161120432. Its totient is φ = 127314161120430.
The previous prime is 127314161120387. The next prime is 127314161120561. The reversal of 127314161120431 is 134021161413721.
It is a weak prime.
It is an emirp because it is prime and its reverse (134021161413721) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 127314161120431 - 241 = 125115137864879 is a prime.
It is a super-3 number, since 3×1273141611204313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (127314161150431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63657080560215 + 63657080560216.
It is an arithmetic number, because the mean of its divisors is an integer number (63657080560216).
Almost surely, 2127314161120431 is an apocalyptic number.
127314161120431 is a deficient number, since it is larger than the sum of its proper divisors (1).
127314161120431 is an equidigital number, since it uses as much as digits as its factorization.
127314161120431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 37.
The spelling of 127314161120431 in words is "one hundred twenty-seven trillion, three hundred fourteen billion, one hundred sixty-one million, one hundred twenty thousand, four hundred thirty-one".
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