Base | Representation |
---|---|
bin | 1011100101001011110011… |
… | …1110000010111001001101 |
3 | 1200002022021021010200020001 |
4 | 2321102330332002321031 |
5 | 3132111103040243413 |
6 | 43025400122524301 |
7 | 2452650563313505 |
oct | 271227476027115 |
9 | 50068237120201 |
10 | 12733453446733 |
11 | 406a255568138 |
12 | 15179b3966691 |
13 | 7149b483b906 |
14 | 320433c4ca05 |
15 | 17135ddb54dd |
hex | b94bcf82e4d |
12733453446733 has 2 divisors, whose sum is σ = 12733453446734. Its totient is φ = 12733453446732.
The previous prime is 12733453446713. The next prime is 12733453446743. The reversal of 12733453446733 is 33764435433721.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12036993096969 + 696460349764 = 3469437^2 + 834542^2 .
It is a cyclic number.
It is not a de Polignac number, because 12733453446733 - 29 = 12733453446221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12733453446713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6366726723366 + 6366726723367.
It is an arithmetic number, because the mean of its divisors is an integer number (6366726723367).
Almost surely, 212733453446733 is an apocalyptic number.
It is an amenable number.
12733453446733 is a deficient number, since it is larger than the sum of its proper divisors (1).
12733453446733 is an equidigital number, since it uses as much as digits as its factorization.
12733453446733 is an evil number, because the sum of its binary digits is even.
The product of its digits is 45722880, while the sum is 55.
The spelling of 12733453446733 in words is "twelve trillion, seven hundred thirty-three billion, four hundred fifty-three million, four hundred forty-six thousand, seven hundred thirty-three".
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