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12737968525253 is a prime number
BaseRepresentation
bin1011100101011100101000…
…0101101100111111000101
31200002201220221001102120102
42321113022011230333011
53132144324420302003
643031424132413445
72453200506664646
oct271271205547705
950081827042512
1012737968525253
114071162177494
121518853a77285
137152540946ca
143207417616cd
15171525481588
hexb95ca16cfc5

12737968525253 has 2 divisors, whose sum is σ = 12737968525254. Its totient is φ = 12737968525252.

The previous prime is 12737968525199. The next prime is 12737968525277. The reversal of 12737968525253 is 35252586973721.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6877390860484 + 5860577664769 = 2622478^2 + 2420863^2 .

It is a cyclic number.

It is not a de Polignac number, because 12737968525253 - 216 = 12737968459717 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 12737968525253.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12737968525853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6368984262626 + 6368984262627.

It is an arithmetic number, because the mean of its divisors is an integer number (6368984262627).

Almost surely, 212737968525253 is an apocalyptic number.

It is an amenable number.

12737968525253 is a deficient number, since it is larger than the sum of its proper divisors (1).

12737968525253 is an equidigital number, since it uses as much as digits as its factorization.

12737968525253 is an evil number, because the sum of its binary digits is even.

The product of its digits is 190512000, while the sum is 65.

The spelling of 12737968525253 in words is "twelve trillion, seven hundred thirty-seven billion, nine hundred sixty-eight million, five hundred twenty-five thousand, two hundred fifty-three".