Base | Representation |
---|---|
bin | 111011010101111100… |
… | …1100000010101000111 |
3 | 110011221101010200200122 |
4 | 1312223321200111013 |
5 | 4041443113431101 |
6 | 134313315132155 |
7 | 12131014245335 |
oct | 1665371402507 |
9 | 404841120618 |
10 | 127438030151 |
11 | 4a05649a283 |
12 | 208468a405b |
13 | c02c188943 |
14 | 624d126b55 |
15 | 34ace9651b |
hex | 1dabe60547 |
127438030151 has 2 divisors, whose sum is σ = 127438030152. Its totient is φ = 127438030150.
The previous prime is 127438030147. The next prime is 127438030211. The reversal of 127438030151 is 151030834721.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 127438030151 - 22 = 127438030147 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (127438030351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63719015075 + 63719015076.
It is an arithmetic number, because the mean of its divisors is an integer number (63719015076).
Almost surely, 2127438030151 is an apocalyptic number.
127438030151 is a deficient number, since it is larger than the sum of its proper divisors (1).
127438030151 is an equidigital number, since it uses as much as digits as its factorization.
127438030151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 35.
Adding to 127438030151 its reverse (151030834721), we get a palindrome (278468864872).
The spelling of 127438030151 in words is "one hundred twenty-seven billion, four hundred thirty-eight million, thirty thousand, one hundred fifty-one".
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