Base | Representation |
---|---|
bin | 1011100101111100111101… |
… | …0001101011000111111111 |
3 | 1200010120022122021121100001 |
4 | 2321133033101223013333 |
5 | 3132320112220442111 |
6 | 43035421134015131 |
7 | 2453625520632604 |
oct | 271371721530777 |
9 | 50116278247301 |
10 | 12746645484031 |
11 | 4074905086aa8 |
12 | 151a4759474a7 |
13 | 71600793a444 |
14 | 320d25cc66ab |
15 | 1718820ec1c1 |
hex | b97cf46b1ff |
12746645484031 has 2 divisors, whose sum is σ = 12746645484032. Its totient is φ = 12746645484030.
The previous prime is 12746645484011. The next prime is 12746645484049. The reversal of 12746645484031 is 13048454664721.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12746645484031 - 231 = 12744498000383 is a prime.
It is a super-2 number, since 2×127466454840312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12746645484011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6373322742015 + 6373322742016.
It is an arithmetic number, because the mean of its divisors is an integer number (6373322742016).
Almost surely, 212746645484031 is an apocalyptic number.
12746645484031 is a deficient number, since it is larger than the sum of its proper divisors (1).
12746645484031 is an equidigital number, since it uses as much as digits as its factorization.
12746645484031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15482880, while the sum is 55.
The spelling of 12746645484031 in words is "twelve trillion, seven hundred forty-six billion, six hundred forty-five million, four hundred eighty-four thousand, thirty-one".
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