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12758004013 is a prime number
BaseRepresentation
bin10111110000110111…
…11011000100101101
31012221010102202101011
423320123323010231
5202112022112023
65505544145221
7631104146656
oct137033730455
935833382334
1012758004013
115457619277
122580768211
131284202501
1489057452d
154ea09e50d
hex2f86fb12d

12758004013 has 2 divisors, whose sum is σ = 12758004014. Its totient is φ = 12758004012.

The previous prime is 12758004001. The next prime is 12758004019. The reversal of 12758004013 is 31040085721.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7370737609 + 5387266404 = 85853^2 + 73398^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12758004013 is a prime.

It is a super-3 number, since 3×127580040133 (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12758004019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6379002006 + 6379002007.

It is an arithmetic number, because the mean of its divisors is an integer number (6379002007).

Almost surely, 212758004013 is an apocalyptic number.

It is an amenable number.

12758004013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12758004013 is an equidigital number, since it uses as much as digits as its factorization.

12758004013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6720, while the sum is 31.

Adding to 12758004013 its reverse (31040085721), we get a palindrome (43798089734).

The spelling of 12758004013 in words is "twelve billion, seven hundred fifty-eight million, four thousand, thirteen".