Base | Representation |
---|---|
bin | 1011100110111010100110… |
… | …0001101111101011101111 |
3 | 1200012011000210112022222101 |
4 | 2321232221201233223233 |
5 | 3133103004130010413 |
6 | 43051155055555531 |
7 | 2455052540156311 |
oct | 271565141575357 |
9 | 50164023468871 |
10 | 12763192031983 |
11 | 4080926191418 |
12 | 152171322bba7 |
13 | 7177439c5813 |
14 | 321a556897b1 |
15 | 171eeeaa2edd |
hex | b9ba986faef |
12763192031983 has 2 divisors, whose sum is σ = 12763192031984. Its totient is φ = 12763192031982.
The previous prime is 12763192031957. The next prime is 12763192032103. The reversal of 12763192031983 is 38913029136721.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12763192031983 - 25 = 12763192031951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12763192031923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6381596015991 + 6381596015992.
It is an arithmetic number, because the mean of its divisors is an integer number (6381596015992).
Almost surely, 212763192031983 is an apocalyptic number.
12763192031983 is a deficient number, since it is larger than the sum of its proper divisors (1).
12763192031983 is an equidigital number, since it uses as much as digits as its factorization.
12763192031983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2939328, while the sum is 55.
The spelling of 12763192031983 in words is "twelve trillion, seven hundred sixty-three billion, one hundred ninety-two million, thirty-one thousand, nine hundred eighty-three".
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