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12765433 is a prime number
BaseRepresentation
bin110000101100…
…100011111001
3220000112212211
4300230203321
511231443213
61133335121
7213335002
oct60544371
926015784
1012765433
11722994a
1243374a1
13284c515
1419a41a9
1511c253d
hexc2c8f9

12765433 has 2 divisors, whose sum is σ = 12765434. Its totient is φ = 12765432.

The previous prime is 12765427. The next prime is 12765439. The reversal of 12765433 is 33456721.

12765433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (12765427) and next prime (12765439).

It can be written as a sum of positive squares in only one way, i.e., 12054784 + 710649 = 3472^2 + 843^2 .

It is an emirp because it is prime and its reverse (33456721) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12765433 - 217 = 12634361 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12765395 and 12765404.

It is not a weakly prime, because it can be changed into another prime (12765439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6382716 + 6382717.

It is an arithmetic number, because the mean of its divisors is an integer number (6382717).

Almost surely, 212765433 is an apocalyptic number.

It is an amenable number.

12765433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12765433 is an equidigital number, since it uses as much as digits as its factorization.

12765433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 15120, while the sum is 31.

The square root of 12765433 is about 3572.8746129692. The cubic root of 12765433 is about 233.7106572999.

The spelling of 12765433 in words is "twelve million, seven hundred sixty-five thousand, four hundred thirty-three".