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12783440095493 is a prime number
BaseRepresentation
bin1011101000000110000001…
…1001111110100100000101
31200021002021220211112101112
42322001200121332210011
53133420441131023433
643104344210134405
72456400363651404
oct272014031764405
950232256745345
1012783440095493
114089476741201
121525624281405
1371961c8b55a2
14322a168a563b
151727d74be348
hexba06067e905

12783440095493 has 2 divisors, whose sum is σ = 12783440095494. Its totient is φ = 12783440095492.

The previous prime is 12783440095453. The next prime is 12783440095519. The reversal of 12783440095493 is 39459004438721.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9095972498209 + 3687467597284 = 3015953^2 + 1920278^2 .

It is a cyclic number.

It is not a de Polignac number, because 12783440095493 - 236 = 12714720618757 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12783440095453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6391720047746 + 6391720047747.

It is an arithmetic number, because the mean of its divisors is an integer number (6391720047747).

Almost surely, 212783440095493 is an apocalyptic number.

It is an amenable number.

12783440095493 is a deficient number, since it is larger than the sum of its proper divisors (1).

12783440095493 is an equidigital number, since it uses as much as digits as its factorization.

12783440095493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26127360, while the sum is 59.

The spelling of 12783440095493 in words is "twelve trillion, seven hundred eighty-three billion, four hundred forty million, ninety-five thousand, four hundred ninety-three".