Base | Representation |
---|---|
bin | 1011101000110100011111… |
… | …0000000010110011010011 |
3 | 1200022021111001200222110102 |
4 | 2322031013300002303103 |
5 | 3134122011301222012 |
6 | 43114205512323015 |
7 | 2460321416614364 |
oct | 272150760026323 |
9 | 50267431628412 |
10 | 12795911351507 |
11 | 4093796407459 |
12 | 1527b249a346b |
13 | 71a859579b0b |
14 | 32347ad15b6b |
15 | 172cb72cb2c2 |
hex | ba347c02cd3 |
12795911351507 has 2 divisors, whose sum is σ = 12795911351508. Its totient is φ = 12795911351506.
The previous prime is 12795911351479. The next prime is 12795911351539. The reversal of 12795911351507 is 70515311959721.
It is a weak prime.
It is an emirp because it is prime and its reverse (70515311959721) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12795911351507 - 234 = 12778731482323 is a prime.
It is a super-2 number, since 2×127959113515072 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12795911350507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6397955675753 + 6397955675754.
It is an arithmetic number, because the mean of its divisors is an integer number (6397955675754).
Almost surely, 212795911351507 is an apocalyptic number.
12795911351507 is a deficient number, since it is larger than the sum of its proper divisors (1).
12795911351507 is an equidigital number, since it uses as much as digits as its factorization.
12795911351507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2976750, while the sum is 56.
The spelling of 12795911351507 in words is "twelve trillion, seven hundred ninety-five billion, nine hundred eleven million, three hundred fifty-one thousand, five hundred seven".
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